Purpose:
To investigate the properties of standing sound waves in an air column
which is open at one end and closed at the other. To determine the
speed
of sound in air.
Discussion:
The speed of sound waves v is related to the frequency f and wavelengthl
by the usual formula v = f l.
We also know that for a pipe filled with air, with one open end and one
closed end, a standing wave is possible if there is a node at the
closed
end and an antinode at (or near) the open end. In this experiment, the
'closed end' corresponds to the surface of the water, and the 'open
end'
is always at the top of the pipe. The apparatus allows you to change
the
length of the air column by changing the water level. A tuning fork of
known frequency f held near the open end will be used to send sound
waves
down the pipe. When the water level is at a standing wave node, the
standing
wave pattern is reinforced, and the sound intensity increases
noticeably.
Procedure:
B. Determine the speed of sound in air under
current
conditions:
Recall vair = fl
1. Determine the resonant wavelength.
• Determine the position of the water level for
successive resonances using one tuning fork.
Find all of the possible resonance positions for
that tuning fork.
• Using node-antinode diagrams determine the
relationship
between the resonant wavelength and the position for successive
resonances.
• Determine a "best" value for the resonant
wavelength
from your data.
2. Calculate vair from f and l.
3. Using the temperature in the lab determine the appropriate value for vair using a formula or by looking up the value in the CRC handbook.
4. Compare your results with the known value. Express the comparison as a % difference.
5. Repeat steps 1 - 4 with a tuning fork having a different frequency.
C. Application: [If you finish steps 1-5,
work on this.]
The human ear is approximately 2.7 cm long. The
canal can be regarded as a tube open at one end and closed at the
other.
What are the frequencies of the 4 harmonics having the lowest
frequencies?
The ear is most sensitive at a frequency of about
3000 Hz. Would you expect that resonance plays a role in this? Explain.